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**A thin wire is attached to a mass M = 3.67 kg, and hung over a pulley. The mass rests on a slope of angle θ = 35 °. The linear mass density of the wire is μ = 7.7 g/m.**

Standing waves are excited in the vertical section of the wire:

The height of this vertical section is h = 2.0 m.

Take g = 9.8 ms−2.

Standing waves are excited in the vertical section of the wire:

The height of this vertical section is h = 2.0 m.

Take g = 9.8 ms−2.

**(a) What is the tension of the wire (you may assume the wire is massless)?**

**I am confused because and I really don't know how to do this question;**

I can't use the formula: [tex]v = \sqrt{\frac{T}{\mu}}[/tex] and then solve like [tex]T = \mu v^2[/tex] because the velocity is not given and I can't think of any way of calculating it..

The correct answer should be 20.6. I don't know what formula to use etc..

Thanks.

I can't use the formula: [tex]v = \sqrt{\frac{T}{\mu}}[/tex] and then solve like [tex]T = \mu v^2[/tex] because the velocity is not given and I can't think of any way of calculating it..

The correct answer should be 20.6. I don't know what formula to use etc..

Thanks.

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