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Terminal speed question

  1. Mar 5, 2015 #1
    1. The problem statement, all variables and given/known data
    A 82kg skydiver can be modeled as a rectangular "box" with dimensions 21cm× 44cm× 1.8m

    2. Relevant equations
    v = sqrt(2mg/(rho * C *A))

    3. The attempt at a solution

    A = 0.21 m * 0.44 m = 0.0924 m^2

    v = sqrt(2 * 82 kg * 9.81 m/s^2 / (1.2 kg/m^2 * 0.0924 m^2 * 0.80))
    =135m/s


    Apparently this is wrong. I have tried many other formulae but I haven't had luck and I have one more attempt remaining. Any ideas?
     
  2. jcsd
  3. Mar 5, 2015 #2

    Svein

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    Why are you assuming that he dives "head first"?
     
  4. Mar 5, 2015 #3
    the question doesnt suggest otherwise, doesn't specify if he dives head first or legs first.
     
  5. Mar 5, 2015 #4

    SteamKing

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    Staff Emeritus
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    What if the skydiver takes this attitude, before the parachute opens?

    freefall2.jpg
     
  6. Mar 5, 2015 #5
    Agreed! Take the largest surface of the box as area.
     
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