- #1

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using the formula [tex]v_t = sqrt(\frac{2*mg}{CpA})[/tex]

[tex]v_t = sqrt(\frac{2*(45g)(9.8m/s^2)}{(.35)(1.2kg/m^3)(0.043m)})[/tex]

so pluggeed that into my calculator, i found the terminal speed of 220.99m/s.

this is where i got stuck, how would i know if it reaches terminal speed or not when dropping from a height of 25m?