1. The problem statement, all variables and given/known data A bobsled has a frontal area of 0.86 m^2 and a coefficient of drag of 0.267. The air density is 1.043 kg/m^3. Total mass of the sled and the bobsled driver and pushers is 827 kg. Friction in the runners is negligible. The track slopes down at an angle of 0.078 radians. What will be the terminal speed (m/s)? m=827kg g=9.81m/s^2 p=1.043kg/m^3 Cd=0.267 A=0.86m^2 2. Relevant equations Fg=mg Fd=.5pCdAv^2 3. The attempt at a solution Fg=Fd but i do not get the right answer. Am I missing something is the angle just to tell you that it is going downhill? mg=.5pCdAv^2 827*9.81=.5*1.043*0.267*0.86*v^2 8112.87=.11974683v^2 v^2=67750.1859548 v=260.289 He wants us to leave all decimals until the final answer which he wants rounded to 3 places.