Given: wooden sphere gravity = 9.8 m/s^2 radius of sphere = .18 m density of sphere = 801 kg/m^3 Drag coefficient = 0.5 I found out the velocity of the wooden ball to be 3.07 m/s (please confirm). Now it has to go through the air that has density of 1.2 kg/m^3. What would be the speed of the sphere falling through this air desity? That's where I'm stuck at. Could anyone expand on how the air density that the ball has to go through is related to the ball's density?