An ice pellet drops from a cloud 1.5 km above the Earth's surface. It's spherical so its drag coefficient is 0.45 and it has radius 0.1 mm. The density of air is 1.2 kg/m^3 and the density of ice is 910 kg/m^3.
What is the terminal speed of the ice pellet?
When the pellet is falling at 1% of its terminal speed, what is the magnitude of its acceleration?
Volume of a sphere= (4/3)(pi)r^3
The Attempt at a Solution
I've tried using D=m/v to solve for the mass of the ice pellet. So (910=m/.000418) and then taking this information and rearranging the FD equation to plug into V^2=square root((2 * m * g) / (Cd * r * A). As you move toward terminal velocity FD=w so FD=mg. I used the mass I got and plugged into that to give me FD and then plugged into the FD equation to solve for V^2 but that wasn't it either. I'm not sure what to do since I do not know FD, Velocity or the mass.
Thanks for your help!