# Termo physics nr1 help

• Termodinamica
So pv/t=p2v2/t2 .Find the pressure at which the gas will have the same volume as at the initial temperature.At 6K the gas will have 3x the volume.At 0.5K the gas will have 1.5x the volume.At 10K the gas will have 10x the volume.At 100K the gas will have 100x the volume.At 500K the gas will have 500x the volume.In summary, at 6K the gas will have 3x the volume, at 0.5K the gas will have 1.5x the volume, at 10K the gas will have 10x the volume, and at 100K the gas will havef

## Homework Statement

In 2 identical containers we have equal mass of helium and Argon at the same temperature.The ratio of the 2 pressures (pressure 1 and pressure 2) knowing that μ helium= 4 kg/kmol and μ argon= 40 kg/kmol is:
a 0.1 b 10 c 5 d 40 e 1/5

i don't know

## The Attempt at a Solution

i don't know

What macroscopic equation gives the behaviour of ideal gases?

idk tell me
i got bad marks at physics

idk =?

pv=nrt?
i don't know man physics is not my main thing

pV=nRT

Correct.

Now see what is identical in both cases and hence try to see on what physical quantity does p depend.

p=nrt/v
?
can you please give more hints?

Temp is the same for both.
What else is the same?

R constant and T
n is the quantity
EDIT:Was joking man i know how to do it p1v=m/miu RT

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Correct.
But if you read the problem CAREFULLY you will notice that there is something else constant.

HAHAAHAH man now i don't understand
p1v=U x R
??

Which gas has the bigger volume?

Which gas has the bigger volume?

Argon i think.

is the argon in a bigger container?

is the argon in a bigger container?

no. what to do?

Each gas in an IDENTICAL container. Hence the volume ...

Ok so volume is constant.Here is what i made so far.
Find p1 and p2
P1=1/μ helium *R
P2=1/μ argon *R

and then P2/P1 = 10.

so from those answers: a) 0.1 b)10 c)5 d)40 e)1/5

the right one is b?

P argon/P helium = 0.1

P helium/P argon = 10

P helium/P argon = 10

so its 10?
i did it good?
can you help me at the other problem too? :D

which problem?

At boiling whit 1K(kelvin) of a gas whit constant pressure the volume is 3 times bigger.The initial temperature of the gas in this process has the value:
a. 6K b 0.5 K c 10K d 100K e 500K

Which equation gives the behaviour of an ideal gas?

pv/t=p2v2/t2

Cross out the P because it is the same on both sides.

yup so v/t = v2/t2 .
What i do next?

Now put in the values you know to get what you do not yet know.

So T2= t1 +1k?
V2 = 3V1?
WE know that the second volume is 3x bigger then the first volume.

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