1)A 3.0kg chair at rest is pulled across the floor by a 20N force.If the co-efficient of friction between the floor and chair is 0.25, calculate:
a)the net force on the chair. answer=13N
b)the displacement of the chair after 2.0sm answer=8.4m
Fn=m*a Fn=Fa+Ff Fg=m*g Ff=m*FT(flipped for perpendicular)
The Attempt at a Solution
I cnat get it started like Im lost with what equation to pick.