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Homework Help: Testing LaTex, don't mind me

  1. May 25, 2006 #1
    [tex]x^2-6x-7/2x^2+3x +1[/tex]
     
  2. jcsd
  3. May 25, 2006 #2
    [tex]\frac{x^2-6x-7}{2x^2+3x+1}[/tex]
     
  4. May 25, 2006 #3
    [tex]\frac{x^2-6x-7}{2x^2+3x+1} x \frac{x^2-6x-7}{2x^2+3x+1} / \frac{x^2-6x-7}{2x^2+3x+1}[/tex]
     
  5. May 25, 2006 #4
    [tex]\frac{x^2-6x-7}{2x^2+3x+1} x \frac{4x^2-16x+15}{2x^2-17x+21} / \frac{4x^2-20x+25}{4x^2-1}[/tex]
     
  6. May 25, 2006 #5
    [tex]\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{2x-3)(x-7)} x \frac{2x+1)(2x-1)}{(2x-5)(2x+5)}[/tex]
     
  7. May 25, 2006 #6
    [tex]\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{(2x-3)(x-7)} x \frac{2x+1)(2x-1)}{(2x-5)(2x+5)}[/tex]
     
  8. May 25, 2006 #7
    [tex]\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{2x-3)(x-7)} x \frac{(2x+1)(2x-1)}{(2x-5)(2x+5)}[/tex]
     
  9. May 25, 2006 #8
    [tex]\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{(2x-3)(x-7)} x \frac{(2x+1)(2x-1)}{(2x-5)(2x+5)}[/tex]
     
  10. May 25, 2006 #9
    [tex]\frac{(2x-1)}{(2x+5)}[/tex]
     
  11. May 25, 2006 #10
    [tex]\frac{5}{(x+3)} - \frac{(1)}{x-1}[/tex]
     
  12. May 25, 2006 #11
    [tex]\frac{5}{(x+3)} - \frac{1}{x-1}[/tex]
     
  13. May 25, 2006 #12
    [tex]\frac{5}{(x+3)} - \frac{(1)}{(x-1)}[/tex]
    [tex]\frac{5(x-1)}{(x+3)(x-1)} - \frac{(x+3))}{(x-1)(x+3)}[/tex]
    [tex]\frac{5(x-1)-(x+3)}{(x+3)(x-1)}[/tex]
    [tex]\frac{5x-5-x-3}{(x+3)(x-1)}[/tex]
    [tex]\frac{4x-8}{(x+3)(x-1)}[/tex]
    [tex]\frac{4(x-2)}{(x+3)(x-1)}[/tex]
     
  14. May 25, 2006 #13

    NateTG

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    Science Advisor
    Homework Helper

    Did you mean:
    [tex]\frac{x^2-6x-7}{2x^2+3x+1} \times \frac{\frac{4x^2-16x+15}{2x^2-17x+21}}{\frac{4x^2-20x+25}{4x^2-1}}[/tex]
     
    Last edited: May 25, 2006
  15. May 25, 2006 #14

    Doc Al

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    Staff: Mentor

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