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Testing population variance

  1. Oct 7, 2014 #1
    1. The problem statement, all variables and given/known data
    Given that 8 person vote for Mr Tan , i cant understand why the probability is sum of 0 people vote for him until 8 people vote for him. Why not the probability = 22c8 ( (0.6)^8 )( (0.4)^14) ?

    2. Relevant equations


    3. The attempt at a solution
     

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  3. Oct 7, 2014 #2

    RUber

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    The probability ##22c8 ( (0.6)^8 )( (0.4)^14)## is the likelihood of drawing exactly this sample assuming the claim is true. When testing the hypothesis, you are comparing the cumulative probability of this sample (at least 8 people), against the claim.
    Note that the expected value, assuming his claim is true would be ##22(.6)=13.2## people. If you just take the probability of 13 people saying they support him, that will not be 50%, but the cumulative probability will be close to that.
     
  4. Oct 9, 2014 #3
    hi, When testing the hypothesis, you are comparing the cumulative probability of this sample (at least 8 people), against the claim

    why the author doesnt say 'the investigator selects a random smaple of 22 people and at most 8 people agree to vote for him ' instead?
     
  5. Oct 9, 2014 #4

    RUber

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    The question is: How likely is it to find something at least as extreme as what was observed? That is normally what people mean when they talk about p-values and significance. It is not: What is the probability of pulling this sample assuming that H0 is true?
    The author may not state it, but that is what is always meant by testing significance.
     
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