- #1

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(Obviously, the function is not differentiable at x=0 so we cannot apply Fermat's critical point theorem).

BiP

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- Thread starter Bipolarity
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- #1

- 775

- 2

(Obviously, the function is not differentiable at x=0 so we cannot apply Fermat's critical point theorem).

BiP

- #2

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- #3

pwsnafu

Science Advisor

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- If ##x>0## then ##f(x) = x## so ##f(x) > 0##,
- If ##x=0## then ##f(x) = x = 0##,
- If ##x < 0## then ##f(x) = -x## and so ##f(x) > 0##,

- #4

chiro

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