''A DART LEAVES THE THROWER HAND HORIZONTALLY AT A height of 1.9m above the ground, calculate the time taken by the dart to reach the board and the horizontal velocity at which the dart left the throwers hand.''(adsbygoogle = window.adsbygoogle || []).push({});

this is what iv worked out

x-0.4

u-?

v-0

a-0

t-?

i than went onto finding the verticle acceleration

x-0.4, u-?, v-0. a-9.81, t-?

v^2=u^2+2ax

v^2-u^2=2ax

v^2-v^2-u^2=2ax-v^2

u^2=2ax-v^2

-u^2=2ax-v^2

2x9.81x0.4=7.84

i than found the square root of 7.84 however it was wrong, since it was -u^2

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# Homework Help: The Acceleration Of Free Fall?

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