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Homework Statement
The angle of the line (x+ SquaredRoot of 3y=12 makes with the positive direction of the x- axis is?
Homework Equations
The Attempt at a Solution
y=mx+c
Make x=0 or y=0
but dont get what to do with it :/...
Welcome to the PF. Is this your equation?Homework Statement
The angle of the line (x+ SquaredRoot of 3y=12 makes with the positive direction of the x- axis is?
Homework Equations
The Attempt at a Solution
y=mx+c
Make x=0 or y=0
but dont get what to do with it :/...
Could you please show your work step-by-step? You need to end up with an equation y = f(x)Hey and thx :)
So the x- axis would be [tex]1/\sqrt[]{}3[/tex]X
Althought what would be the angle of the equation exactly
Its a Multiple Choice:
A) 30 Deg.
B) 120 Deg.
C) 150 Deg.
D) 60 Deg.
That does not look right. When you start with this:Well y=-(1/squared root 3)x+12/squared root 3
and f(x)=-[tex]1/\sqrt{}3x[/tex]+[tex]12/\sqrt{}3[/tex]
and by using the 1,2 and[tex]\sqrt{}3[/tex] triangle
I got 30 Deg. :/?
No, sorry. We do not give answers here on the PF.I am struggling with much demand of help in need :/
and as i have exam tomorrow i really need to brush off all these kinds of exact value questions...
Pls can you help me and answer it so i can see where to get the answer :)?
Great! You're almost there...Okay so what I have done is:
1) Make everything to y= which is:
[tex]\sqrt{}3[/tex]y= -x+12
2) take the Squared root over to make it:
3y=x(squared)-24x+144
If you have taken calculus, you would differentiate the equation to get dy/dx, and set the x and y values to where the curve y = f(x) crosses the x-axis.Yeah, okay, but how do we get the angle from that equation though?
You forgot to take the 3 across the = sign from the LHS to the RHS.dy/dx of the equation= 2x-24