1. Ut will bungee jump from the golden gate bridge. The height that she will jump from is 65 meters. The rope pulls her up 8 meters above the water. If UT's weight is 63 kg, how far will the rubber rope pull her upwards, if there's no loss to friction or air resistance? 2. Relevant equations PE= mgh v=√2gh v^2-u^2=2as 3. The attempt at a solution I started by calculating the energy of the fall. PE= 63*(65-8)*9.8= 35191 J I then tried to calculate the velocity that she reaches when she is about to fall. v=√2gh= 33.45 m/s I then used v^2-u^2=2as, u^2 at the top is 0 and a= g=9.8 and s=h v^2-u^2=2as 33.45^2-0= 2*9.82* s s= 55.4 meters That seems oddly wrong that she could reach such a height, is this the right way to do it or is there a mistake?