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The Carnot Icemaker

  1. May 9, 2008 #1
    An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 C and rejects heat to a room at a temperature of 22.2 C. Suppose that liquid water with a mass of 86.2 kg at 0.0 C is converted to ice at the same temperature. Take the heat of fusion for water to be L_f = 3.34×10^5 J/kg.

    How much heat |Q_H| is rejected to the room?

    Q_H = -W = nRT_H(lnV2/V1)

    (V2/V1)^gamma-1 = T1/T2 = Tc/Th
     
  2. jcsd
  3. May 9, 2008 #2

    Chi Meson

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    this part is not correct. The ejected heat into the room is more than the work done.
    This is not a required formula. Consider the Carnot efficiency formula
     
  4. May 10, 2008 #3
    i figured out the Qh and got 3.113x10^7 J but now it wants to know how much Energy E must be supplied to the engine, in joules. I know that E_int= Q+W but says im wrong... any help?
     
  5. May 10, 2008 #4

    alphysicist

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    Hi horsegirlf09,

    There are three energy transfers to keep track of: Qc, which is the heat removed from the cold reservoir or system; Qh, which is the heat expelled into the hot reservoir; and W, which is the work done by the engine. How are these three related?
     
  6. Feb 13, 2009 #5
    An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 degrees Celsius and rejects heat to a room at a temperature of 26.0 degrees Celsius. Suppose that the liquid water with a mass of 70.0 kg at 0.0 degrees Celsius is converted to ice at the same temperature. Take the heat of fusion for water to be L_f = 3.34x10^5 J/kg. How much heat |Q_H| is rejected to the room? Express your answer in joules to four significant figures.

    I get this information to some site that i get research in google search....



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