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1. The problem statement, all variables and given/known data

Sea clams move by pushing water in one direction so that the water pushes them in the opposite direction. In doing so a 0.5 kg clam can accelerate 0.6 kg of water from rest to a speed of 1.9 m/s in 0.43 seconds. Calculate the magnitude of the clam's acceleration

2. Relevant equations

F= ma

Vf^2= V0^2 + 2ax

Vf= V0 + at

x= V0*t + .5a(t^2)

3. The attempt at a solution

I'm not sure why my answer isn't checking out. The initial velocity is 0. The final velocity is 1.9. The time is .43. These all fit into the third equation: 1.9= 0 + .43a. a then equals 4.42. This, however, is not working as my answer. What am I missing?

Thanks in advance!

~Phoenix

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# Homework Help: The Clam and Its Forces

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