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The concept of a rate

  1. Mar 19, 2013 #1
    The concept of a "rate"

    Here's another question from good ol square :|

    I was hoping to get some clarification about the concept of a rate of two quantities, with different units, like speed [itex]\frac{a-units}{b-units}[/itex]. How does the expression for division [itex]\frac{a-units}{b-units}[/itex] arise from the statement like 'a' meters per 'b' seconds?

    If I were to plot meters vs. time for some object moving at constant speed, I can get the 'rate' of the curve by using the definition of slope like we were taught Δmeters/Δtime ie the speed.

    I also understand that acceleration is the change in velocity, 'per' given desired time interval ie Δvelocity/Δtime.

    In both cases, I don't think I have conceptual issue with why it makes sense to define these rates of change with respect to time, I just don't understand what division has to do with it - multiple subtractions of units of time, from the numerator?? :S Thanks.
     
  2. jcsd
  3. Mar 19, 2013 #2

    tiny-tim

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    Hi Square1! :smile:
    The slope is a division: units up over units across.

    (and i don't understand the last part of your question, about subtractions)
     
  4. Mar 19, 2013 #3

    HallsofIvy

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    "per" means "divide".
     
  5. Mar 19, 2013 #4
    A ball rolls 5 feet every 30 seconds. How far has it rolled after 3 minutes (solve without using fractions)? How did you reason out your answer? Is it a bit like "There are 5 feet attributed to every slice of 30 seconds, so I just have to find how many slices of 30 seconds fit into 3 minutes" ? That's pretty much the motivation for a fraction: one property is directly associated to a certain amount of a different property, so operations with that property correspond to operations on the proper corresponding multiple of the first property.
     
  6. Mar 19, 2013 #5
    Thank you for the feedback everyone. I am backing out of this question though. I don't know if I am overthinking it or something, but I am having a "I'm not exactly sure what my own problem even is" moment. Although, there is something I'm not getting :S Maybe I'll come back to it another time.
     
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