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The problem is to show [itex]sin\overline{z} = \overline{sinz}[/itex]. What I need is help to get going.

We know that [itex]sinz = \frac{e^{iz}-e^{-iz}}{2i}[/itex]

I can't see the first step in this. What I've tried to do is expressing [itex]sin\overline{z} [/itex] and [itex] \overline{sinz} [/itex] in terms of the above equation, but I don't know how to write the conjugate of [itex]\frac{e^{iz}-e^{-iz}}{2i}[/itex]. Of course I know the conjugate of a regular complex number, [itex]\overline{z} = x - iy[/itex]. How do these relate?

We know that [itex]sinz = \frac{e^{iz}-e^{-iz}}{2i}[/itex]

I can't see the first step in this. What I've tried to do is expressing [itex]sin\overline{z} [/itex] and [itex] \overline{sinz} [/itex] in terms of the above equation, but I don't know how to write the conjugate of [itex]\frac{e^{iz}-e^{-iz}}{2i}[/itex]. Of course I know the conjugate of a regular complex number, [itex]\overline{z} = x - iy[/itex]. How do these relate?

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