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Calculating Electric Flux in a Nonuniform Field: A Cubic Box Example
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[QUOTE="kopinator, post: 4511023, member: 457159"] A cubic box of side a = 0.410 m is placed so that its edges are parallel to the coordinate axes, as shown in the figure. There is NO net electric charge inside the box, but the space in and around the box is filled with a nonuniform electric field of the following form: E(x,y,z) = Kz j + Ky k, where K = 3.40 N/(Cm) is a constant. What is the electric flux through the top face of the box? (The top face of the box is the face where z = a. Remember that we define positive flux pointing out of the box.) Flux= ∫E*dA *= dot product I started my integral off with ∫(3.40j + 3.40k)*dxdy and worked it down to: ∫∫3.40dxdy where the boundaries of both integrals go from 0-.410. My final answer was .571 N*m^2/C but it was wrong. Where did I mess up along the way? Am I missing a key part of the question? [/QUOTE]
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Calculating Electric Flux in a Nonuniform Field: A Cubic Box Example
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