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## Homework Statement

Evaluate ∇ x [itex]\overline{F}[/itex], with [itex]\overline{F}[/itex]([itex]\overline{r}[/itex]) = [itex]\overline{r}[/itex]lnr, where [itex]\overline{r}[/itex] = (x; y; z) is the position vector and r is the modulus of the position vector.

## Homework Equations

The curl of a vector

## The Attempt at a Solution

I recognise I am evaluating the curl of the Vector F, however when taking the derivatives of the x, y and z components respectively. I'm not sure if it should be as follows. (showing the first bit of the problem)

([itex]∂F(z)/∂y[/itex] - [itex]∂F(y)/∂Z[/itex]), ...

which becomes

(∂[itex]\overline{r}[/itex](z)lnr/∂y) - (∂[itex]\overline{r}[/itex](y)lnr/∂Z),

Im not sure if this is right and if I need to include the modulus of the vector r when differentiating [itex]\overline{r}[/itex]lnr with respect to y or z.