The current in RLC circuit.

  • #1
Asmaa Mohammad
182
7

Homework Statement


In the tuned circuit below, what will happen to the reading of the ammeter when:
a) source frequency increases. The voltage is constant
b) the capacitance increases. The voltage and source frequency are constant
c) The voltage increases. Source frequency is constant.
R8vfj.jpg



Homework Equations


ƒ =1/(2π√LC) Where: C is the capacitance and L is the inductance.
I= V/Z Where: V is the voltage and Z is the impedance.
Xc=1/ωC
Xl=ωL
Z=√R²+(Xl-Xc)²

The Attempt at a Solution


Here is my solution:

a) the ammeter reading decreses.
Explanation: when source frequency varies the circuit is no longer in resonance so the impedance increases,
Z=√R²+ (Xl-Xc)²

b) the ammeter reading decreases.
Explanation: when the capacitance C increases, Xc decrease, then (Xl-Xc) increses, hence the impedance increases because:
Z= √R²+(Xl-Xc)²

c) the ammeter reading increases.
Explanation: since source frequency is constant, the circuit is still in resonance. So, increasing in voltage will increase the current becuase the impedance of the circuit will not change.

Am I correct?
 

Answers and Replies

  • #2
ehild
Homework Helper
15,543
1,915

Homework Statement


In the tuned circuit below, what will happen to the reading of the ammeter when:
a) source frequency increases. The voltage is constant
b) the capacitance increases. The voltage and source frequency are constant
c) The voltage increases. Source frequency is constant.
R8vfj.jpg



Homework Equations


ƒ =1/(2π√LC) Where: C is the capacitance and L is the inductance.
I= V/Z Where: V is the voltage and Z is the impedance.
Xc=1/ωC
Xl=ωL
Z=√R²+(Xl-Xc)²

The Attempt at a Solution


Here is my solution:

a) the ammeter reading decreses.
Explanation: when source frequency varies the circuit is no longer in resonance so the impedance increases,
Z=√R²+ (Xl-Xc)²

b) the ammeter reading decreases.
Explanation: when the capacitance C increases, Xc decrease, then (Xl-Xc) increses, hence the impedance increases because:
Z= √R²+(Xl-Xc)²

c) the ammeter reading increases.
Explanation: since source frequency is constant, the circuit is still in resonance. So, increasing in voltage will increase the current becuase the impedance of the circuit will not change.

Am I correct?
Yes, it is correct. Well done!
 
  • #3
Asmaa Mohammad
182
7
Yes, it is correct. Well done!
Thank you, ehild!
 

Suggested for: The current in RLC circuit.

Replies
20
Views
315
  • Last Post
2
Replies
52
Views
993
Replies
39
Views
913
  • Last Post
Replies
12
Views
1K
  • Last Post
Replies
3
Views
393
Replies
1
Views
270
  • Last Post
Replies
10
Views
552
Top