In the tuned circuit below, what will happen to the reading of the ammeter when:
a) source frequency increases. The voltage is constant
b) the capacitance increases. The voltage and source frequency are constant
c) The voltage increases. Source frequency is constant.
ƒ =1/(2π√LC) Where: C is the capacitance and L is the inductance.
I= V/Z Where: V is the voltage and Z is the impedance.
The Attempt at a Solution
Here is my solution:
a) the ammeter reading decreses.
Explanation: when source frequency varies the circuit is no longer in resonance so the impedance increases,
b) the ammeter reading decreases.
Explanation: when the capacitance C increases, Xc decrease, then (Xl-Xc) increses, hence the impedance increases because:
c) the ammeter reading increases.
Explanation: since source frequency is constant, the circuit is still in resonance. So, increasing in voltage will increase the current becuase the impedance of the circuit will not change.
Am I correct?