A 60.0 hollow nichrome tube of inner diameter 1.60 , outer diameter 4.20 is connected to a 4.00 battery.What is the current in the tube?
[tex]\rho[/tex] = 1.5*10^-6 ohm for nichrome
R=[tex]\rho[/tex]L/A -a should be the crossectional area
The Attempt at a Solution
need R so use R=pL/A
plug into R
then use the resistance to solve for current of the wire
This isn't the right answer and I don't know what I did wrong! Could someone help me out here, please!