(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 60.0 hollow nichrome tube of inner diameter 1.60 , outer diameter 4.20 is connected to a 4.00 battery.What is the current in the tube?

[tex]\rho[/tex] = 1.5*10^-6 ohm for nichrome

2. Relevant equations

I=dletaV/R

R=[tex]\rho[/tex]L/A -a should be the crossectional area

3. The attempt at a solution

need R so use R=pL/A

A=(4.2E-3)^2(pi)-(1.6E-3)^2(pi)=4.7375E-5m

plug into R

R=((1.5E-6ohm)(0.6m))/(4.7375E-5m)=0.0189972 ohms

then use the resistance to solve for current of the wire

I=4V/0.0189972ohm=210.6A

This isn't the right answer and I don't know what I did wrong! Could someone help me out here, please!

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: The current of a nichrome tube

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