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Lorentz Transformation says

[tex]x'=\frac{x-ut}{\sqrt{1-u^2/c^2}}[/tex]

Does its derivative

[tex]\frac{dx'}{dt}=\frac{dx/dt-u}{\sqrt{1-u^2/c^2}}[/tex]

give the velocity addition equation?

[tex]x'=\frac{x-ut}{\sqrt{1-u^2/c^2}}[/tex]

Does its derivative

[tex]\frac{dx'}{dt}=\frac{dx/dt-u}{\sqrt{1-u^2/c^2}}[/tex]

give the velocity addition equation?

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