- #1

mighty2000

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question:

Gravel is continiously being poured at the rate dm/dt = 80kg/s on a conveyor belt moving at 4.5 m/s. What is the power required to operate the conveyor belt?

my answer:

power required = work done on the gravel per second=ma(v)

v = velocity of the conveyor belt.

so

P=80.0 kg/s * 4.5 m/s * 4.5 J/s =1620 Watts

Now I have a problem with my formula.

will this give me watts or some other unit of measurement?

also, is the problem even close to being correct?

thanks in advance all.

M2k