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Introductory Physics Homework Help
The Field of an Electric Dipole
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[QUOTE="Violagirl, post: 4535409, member: 437260"] [h2]Homework Statement [/h2] Consider an electric dipole in the attached document. At point P, the fields E[SUB]+[/SUB] due to q+ and E[SUB]-[/SUB] due to q- are: E[SUB]+[/SUB] = kq/(r-a)[SUP]2[/SUP], E[SUB]-[/SUB] = -kq/(r+a)[SUP]2[/SUP] Then total field at P is: E = E[SUB]+[/SUB] + E[SUB]-[/SUB] = kq [ 1/(r-a)[SUP]2[/SUP] - 1/(r+a)[SUP]2[/SUP]] y-hat [h2]Homework Equations[/h2] See question 1. [h2]The Attempt at a Solution[/h2] So this post is just trying to comprehend the example problem above. I don't believe I'm fully understanding electric field. In the problem above, they have a point P without a charge given. They say that the impact of the electric field of +q occurs at a distance of r-a which makes sense if P is a postive charge. But then for -q, it takes place at a distance of r+a. What I don't understand for this, shouldn't it take place at a distance of 2a+r? It seems like it'd be a distance of 2a from Point P. Or are we considering that the electric field is moving towards -q? I'm not sure I understand this problem... [/QUOTE]
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The Field of an Electric Dipole
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