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kelvin56484984
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1. Homework Statement
how to get
R=Vi 2 sin2θ/g
y=x*tanθ-[x2*g]/[2(Vi*cosθ)2]
Homework Equations
Vy=Vi*sinθ-gt
y=Vi*sinθ*t-1/2gt^2
Vx=Vi*cosθ
x=Vi*cosθ*t
The Attempt at a Solution
I use this formula to find the expression for t
Vy=Vi*sinθ-gt
gt=Vi*sinθ
t=Vi*sinθ/g
I substitute it into xf=xi+Vi*t+1/2at^2 (a=0)
xf=xi+Vi*cosθ*t
I get
R=Vi2*sinθcosθ/g
But the correct one is R=Vi2*2sinθcosθ/g
What's wrong with it?
I also see this formula in my book
y=xtanθ - [x2*g]/[2(Vi*cosθ)2]
how to figure out it?
thank you
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