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The full way of different result to a different presentation

  1. Feb 20, 2009 #1
    [tex]
    \begin{pmatrix}
    0 & 2 & -3 & 2\\
    1 & a &-1 &-4 \\
    2&1 &-1 &-2 \\
    3 &0 &0 &-6
    \end{pmatrix}
    [/tex]
    next
    [tex]
    \begin{pmatrix}
    1 &0 &0 &-2 \\
    0&2 &-3 &2 \\
    1& a &-1 &-4 \\
    2&1 &-1 &-2
    \end{pmatrix}
    [/tex]
    next
    [tex]
    \begin{pmatrix}
    1& 0 &0 &-2 \\
    0&2 &-3 &2 \\
    0&a &-1 &-2 \\
    0&1 &-1 &2
    \end{pmatrix}
    [/tex]
    next
    [tex]
    \begin{pmatrix}
    1 &0 &0 &-2 \\
    0&1 &-1 &2 \\
    0&0 &a-1 &-2-2a \\
    0&0 &-1 &-2
    \end{pmatrix}
    [/tex]
    next

    [tex]
    \begin{pmatrix}
    1 &0 &0 &-2 \\
    0&1 &0 &4 \\
    0&0 &1 &2 \\
    0&0 &a-1 &-2-2a
    \end{pmatrix}
    [/tex]
    next
    [tex]
    \begin{pmatrix}
    1 &0 &0 &-2 \\
    0&1 &0 &4 \\
    0&0 &1 &2 \\
    0&0 &0 &-4a
    \end{pmatrix}
    [/tex]
    but when ill present the vectors as rows ill get
    [tex]
    \begin{pmatrix}
    0&1 &2 &3 \\
    2&a &1 &0 \\
    -3&-1 &-1 &0 \\
    2& -4 &-2 &-6
    \end{pmatrix}
    [/tex]
    next
    [tex]

    \begin{pmatrix}
    2&a &1 &0 \\
    0&1 &2 &3 \\
    -3&-1 &-1 &0 \\
    2& -4 &-2 &-6
    \end{pmatrix}
    [/tex]
    next
    [tex]


    \begin{pmatrix}
    2&a &1 &0 \\
    0&1 &2 &3 \\
    0&3a-2 &1 &0 \\
    0& -a-4 &-3 &-6
    \end{pmatrix}
    [/tex]
    L_3 *(a+4) +L_4*(3a-2)=>L_4
    [tex]

    \begin{pmatrix}
    2&a &1 &0 \\
    0&1 &2 &3 \\
    0&3a-2 &1 &0 \\
    0& 0 &-8a+10 &-18a+12
    \end{pmatrix}
    [/tex]

    see i get different results
    so it does matter??
     
    Last edited: Feb 20, 2009
  2. jcsd
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