The full way of different result to a different presentation

[tex]
\begin{pmatrix}
0 & 2 & -3 & 2\\
1 & a &-1 &-4 \\
2&1 &-1 &-2 \\
3 &0 &0 &-6
\end{pmatrix}
[/tex]
next
[tex]
\begin{pmatrix}
1 &0 &0 &-2 \\
0&2 &-3 &2 \\
1& a &-1 &-4 \\
2&1 &-1 &-2
\end{pmatrix}
[/tex]
next
[tex]
\begin{pmatrix}
1& 0 &0 &-2 \\
0&2 &-3 &2 \\
0&a &-1 &-2 \\
0&1 &-1 &2
\end{pmatrix}
[/tex]
next
[tex]
\begin{pmatrix}
1 &0 &0 &-2 \\
0&1 &-1 &2 \\
0&0 &a-1 &-2-2a \\
0&0 &-1 &-2
\end{pmatrix}
[/tex]
next

[tex]
\begin{pmatrix}
1 &0 &0 &-2 \\
0&1 &0 &4 \\
0&0 &1 &2 \\
0&0 &a-1 &-2-2a
\end{pmatrix}
[/tex]
next
[tex]
\begin{pmatrix}
1 &0 &0 &-2 \\
0&1 &0 &4 \\
0&0 &1 &2 \\
0&0 &0 &-4a
\end{pmatrix}
[/tex]
but when ill present the vectors as rows ill get
[tex]
\begin{pmatrix}
0&1 &2 &3 \\
2&a &1 &0 \\
-3&-1 &-1 &0 \\
2& -4 &-2 &-6
\end{pmatrix}
[/tex]
next
[tex]

\begin{pmatrix}
2&a &1 &0 \\
0&1 &2 &3 \\
-3&-1 &-1 &0 \\
2& -4 &-2 &-6
\end{pmatrix}
[/tex]
next
[tex]


\begin{pmatrix}
2&a &1 &0 \\
0&1 &2 &3 \\
0&3a-2 &1 &0 \\
0& -a-4 &-3 &-6
\end{pmatrix}
[/tex]
L_3 *(a+4) +L_4*(3a-2)=>L_4
[tex]

\begin{pmatrix}
2&a &1 &0 \\
0&1 &2 &3 \\
0&3a-2 &1 &0 \\
0& 0 &-8a+10 &-18a+12
\end{pmatrix}
[/tex]

see i get different results
so it does matter??
 
Last edited:

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