- #1

- 220

- 0

**Fundamental Postulate Of Special Relativity:**The speed of a photon in any inertial reference frame must be measured as c, where c = 299792458 meters per second.

It is provable within the framework of the special theory of relativity, that

**Theorem Of Special Relativity:**If all coordinates of reference frame F2 are moving in a straight line at a constant speed in some inertial reference frame F1, then F2 is also an inertial reference frame.

Let F1 be an inertial reference frame. Let two photons be moving in the same direction in F1.

By the fundamental postulate of the theory of special relativity, the speed of photon A in inertial reference frame F1 is 299792458 meters per second.

By the fundamental postulate of the theory of special relativity, the speed of photon B in inertial reference frame F1 is 299792458 meters per second.

Since they are moving in the same direction, the difference in their velocity vectors (as defined in F1) is equal to zero. Thus, the two photons are not moving relative to each other.

Define coordinate system F2, to have photon A as origin, and let the unit vector on the positive x axis point to photon B. By the previously mentioned theorem of SR, F2 is an inertial reference frame.

Now, since the photons are not moving relative to each other, the speed of photon B in F2 is equal to zero. And F2 is an inertial reference frame.

By the fundamental postulate of the special theory of relativity, the speed of photon B must equal 299792458 meters per second in any inertial reference frame, hence by the fundamental postulate of SR, the speed of photon B in F2 must equal 299792458 m/s, therefore the speed of photon B in F2 isn't equal to zero.

Hence, we arrive at the following explicit contradiction:

The speed of photon B in F2 is equal to zero, and the speed of photon B in F2 isn't equal to zero.

Therefore, the fundamental postulate of the theory of special relativity is false.

QED

Respectfully,

The Star

Last edited: