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s = ct

The amount of motion p of the smallest particles moving in circles might or might not be mc/(2(pi)) = mv

and thereby v = c/(2(pi)) (the average value anyway, the acceleration is constant.)

since:

v_{0}/(1 - (v/c)^{2})^{½}

= v_{1}/(1 - (v/c)^{2})^{½}

we know that:

a_{0}/(1 - (v/c)^{2})^{½}+ v_{0}/c^{2}/(1 - (v/c)^{2})^{½}

= a_{1}/(1 - (v/c)^{2})^{½}+ v_{1}/c^{2}/(1 - (v/c)^{2})^{½}= the acceleration.

and thereby:

a_{0}/(1 - (v/c)^{2})^{½}+ c/(2(pi))_{0}/c^{2}/(1 - (c/(2(pi))/c)^{2})^{½}

= a_{1}/(1 - (c/(2(pi))/c)^{2})^{½}+ v_{1}/c^{2}/(1 - (c/(2(pi))/c)^{2})^{½}= the acceleration.

the second term (c/(2(pi)) should be the gravityconstant.

But the force of gravity decreases sphearically. So the gravityconstant we use is actually 1/(8(pi)^{2}c).

At large range the speed of light can be aproximated to 299792458 m/s.

If anyone can confirm this, please do...

(It's easy to prove that it stands if you prove that the speed is

c/(2(pi))).

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# The GF (The gravitational force)

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