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The graphic of |F||D|=1 is hyperbola or ellipse

  1. Sep 2, 2004 #1
    |F||D|=1 is the simplest form of the law of lever in equilibrium.
    If |F|=|x-y| and |D|=x+y then |x^2-y^2|=1 is an real hyperbola.
    In this case the interaction is repulsive.
    If |F|=x-iy and |D|=x+iy then x^2+y^2=1 is an real ellipse or imaginary hyperbola.
    In this case the interaction is attractive.

    www.geocities.com/dedaNoe
    www.geocities.com/dedaNoe/lever.pdf
     
  2. jcsd
  3. Sep 2, 2004 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Perhaps it would help us understand what in the world you are talking about if you told us what F and D mean!
     
  4. Sep 3, 2004 #3
    Yeah sure!

    F is the force acting in D distance from the center of the lever.
    The common version of the law of lever is:
    |F||D|=|F_r||D_r|=1
    here |F_r| is the sum of the forces from the rest of the system and
    |D_r| is the sum of the distances from the rest of the system.

    I have more on this on my page:
    www.geocities.com/dedaNoe
    section "Dynamics of the lever".
     
  5. Sep 3, 2004 #4

    Doc Al

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    Staff: Mentor

    I think we've seen enough.
     
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