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I The hamiltonian operator

  1. Mar 28, 2016 #1
    I came across a previous exam question which stated: Do all physical states, ψ, abide to Hψ = Eψ. I thought about it for a while, but I'm not really sure.
  2. jcsd
  3. Mar 28, 2016 #2


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    Not all, only eigenstates of the (time-independent) Hamiltonian satisfy that equation.
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