# The incredible lifting machine heat loss?

the incredible lifting machine heat loss??

While stumbling upon this website on the Incredible lifting machine,

http://tigre.ucr.edu/dipen/phy11/heat.htm
I was wondering what could be some of the reasons why the work down calculated as in mgh does not equal to the work done under the pv graph?

I thought it should be the same? if not, that means there is heat loss by via what means???

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Andrew Mason
What suggests to you that the increase in potential mechanical energy of the system is not equal to $\int Pdv$?