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The kissing circle

  1. Sep 22, 2009 #1
    The "kissing circle"

    1. The problem statement, all variables and given/known data
    An object moving at a constant speed of 31 m/s is making a turn with a radius of curvature of 4 m (this is the radius of the "kissing circle"). The object's momentum has a magnitude of 87 kg·m/s.
    What is the magnitude of the rate of change of the momentum?
    What is the magnitude of the net force?


    2. Relevant equations
    p = mv
    [tex]\Delta[/tex]p = Fnet[tex]\Delta[/tex]t
    dp/dt = magnitude of V / R (sry dont know how to put that in latex)

    3. The attempt at a solution
    Question 1: Velocity divided by radius? Using the 3rd equation, but the units dont check out.
    I am lost
    Question 2: How do I find t, and afterwards, the answer would be Fnet = 87 (change in momentum) * t (change in time)
     
  2. jcsd
  3. Sep 22, 2009 #2

    rock.freak667

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    Homework Helper

    Re: The "kissing circle"

    the rate of change of momentum is just acceleration so you need to find the centripetal acceleration.
     
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