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The kronecker delta

  1. Feb 19, 2007 #1
    I keep seeing this come up in relativity and tensor resources but I have no idea wht the heck it means. Could someone explain it to me?
     
  2. jcsd
  3. Feb 19, 2007 #2
  4. Feb 19, 2007 #3
    The Kronecker delta is a function of two integers. If the integers are the same then the value of the function is 1. Otherwise it is zero. This function can be represented as a matrix. The notation for this function is [itex]\delta[/itex]ij.

    Pete
     
  5. Feb 19, 2007 #4

    Why is it important in tensor analysis?
     
  6. Feb 19, 2007 #5

    George Jones

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    Example from relativity. Let the coordinates of an event be [itex]\left\{x^0 , x^1 , x^2 , x^3 \right\}.[/itex] Then, using the summation convention of summing over repeated indices,

    [tex]x^\mu \delta_{\mu \nu} = x^0 \delta_{0 \nu} + x^1 \delta_{1 \nu} + x^2 \delta_{2 \nu} + x^3 \delta_{3 \nu}.[/tex]

    Since the Kronecker delta is zero unless both indices are equal, only one of the terms in the above sum survives. We don't know which one, but we know it's the one that has [itex]\nu[/itex] as its first index. Therefore, the sum equals [itex]x^\nu .[/itex]
     
    Last edited: Feb 19, 2007
  7. Feb 19, 2007 #6
    because it's a metric tensor of euclidean space? dunno. the "importance" asigned to things by different people is quite biased.
     
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