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The Landau Gauge

  1. Jan 3, 2008 #1
    Could anybody explain to me the difference between a Landau Gauge and Symmetric Gauge?

    I know the Landau Gauge is given by A = (0,Bx,0) producing a constant magnetic field in the z direction. I am *assuming* (process of elimination!) that A = ½B × r = (-yB/2,xB/2,0) is an example of a symmetric gauge which, likewise, corresponds to a constant z magnetic field.

    I'm really after some clarification in terms of how the gauge chosen for a magnetic field affects the Schrodinger equation for a charged particle. If anyone could point me in the right direction I'd be very grateful! Thanks in advance.
  2. jcsd
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