- #1
Spectre5
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I know that the limit as cos(t) goes to infinity is undefined becuase cosine oscillates between plus and minus one.
Now I have this limit to compute:
Limit of [ (t * cost(t)) / (e^(t)) ] as t goes to infinity
I know that the answer is 0 and I intuitively know why (because exp raises value far quicker than just t)
But, how do I go about proving this...the top is undefined and using LoHospitals rule gets no where becuase a (t * sin(t)) will still be in the numerator.
So how do I go about doing this? Can I just ignore the affects of the cos and just use LoHospitals rule for t/e^t??
Thanks for any help
Now I have this limit to compute:
Limit of [ (t * cost(t)) / (e^(t)) ] as t goes to infinity
I know that the answer is 0 and I intuitively know why (because exp raises value far quicker than just t)
But, how do I go about proving this...the top is undefined and using LoHospitals rule gets no where becuase a (t * sin(t)) will still be in the numerator.
So how do I go about doing this? Can I just ignore the affects of the cos and just use LoHospitals rule for t/e^t??
Thanks for any help