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naranekkosh

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- Thread starter naranekkosh
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naranekkosh

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turbo

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The Roche radius is not a fixed barrier below which an orbiting body is pulled to the larger body. It is the critical distance closer than which an orbiting body will be tidally disrupted and torn apart by the larger body. There are many variables that affect the limit of any particular orbiting body, including relative density and tensile strength. This will help:naranekkosh said:

http://www.answers.com/topic/roche-limit

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SpaceTiger

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Perhaps you should look instead at the Hill Sphere, the approximate distance from the moon at which a satellite could have a stable orbit. It's somewhat related to the *Roche lobe*, so maybe that's what you were thinking of. Anyway, it would be given by:

[tex]r=r_m(\frac{M_m}{3(M_m+M_e)})^{1/3}[/tex]

This gives a distance of 15% the distance between the Earth and the moon (~60,000 km). There would be other corrections due to the sun's gravity, however, and I won't try to approximate those.

Oh, and for any reasonably-sized satellite, this wouldn't depend on the properties of the satellite.

[tex]r=r_m(\frac{M_m}{3(M_m+M_e)})^{1/3}[/tex]

This gives a distance of 15% the distance between the Earth and the moon (~60,000 km). There would be other corrections due to the sun's gravity, however, and I won't try to approximate those.

Oh, and for any reasonably-sized satellite, this wouldn't depend on the properties of the satellite.

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Billy T

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Thanks for infro - I had never heard of "Hill Sphere" before, but knew about Roche limit. I believe R.L. sets a limit on when the Earth got it's moon as reversing time and making reasonable assumptions about tidal dissipation, torques, land /water geometry, etc. one can calculate how long ago the moon would have been at the Roche limit. Days would have been much shorter then and tides much larger.SpaceTiger said:Perhaps you should look instead at the Hill Sphere, the approximate distance from the moon at which a satellite could have a stable orbit. It's somewhat related to theRoche lobe, so maybe that's what you were thinking of. Anyway, it would be given by:

[tex]r=r_m(\frac{M_m}{3(M_m+M_e)})^{1/3}[/tex]

This gives a distance of 15% the distance between the Earth and the moon (~60,000 km). There would be other corrections due to the sun's gravity, however, and I won't try to approximate those.

Oh, and for any reasonably-sized satellite, this wouldn't depend on the properties of the satellite.

I think the Earth is older, so we definitely got it later, not at same time as Earth was forming. I also think I have read that the tides would have been more than 100 feet of tide in open ocean. -Do you know anything about this? With two large tides coming every day (of much less than 24 hours) it seems very reasonable that life in the water would be the obvious choice, but I don't know much about how this "short days/ large tides" period relates to the origin of life.

Also there may be another limit of interest. Like Roche limit, its value would depend upon the particular body orbiting. Thus I will assume a "dumb bell" of two equal masses separated by a semis-rigid rod of 100 feet (or meters, if you like). Rod is "semi-rigid" so when it flexes, it dissipates energy. In the moon's gravity gradient the dumb bell can have the rod axis pointing at the center of the moon, provided it is orbit about the moon

My second question (and assumption) is about the maximum altitude of the dumb bell in which it is stably pointing at the moon. (good for communication antennas relaying msg between settlements in different locations) Is it the same as the Hill limit or smaller? (Lets neglect the Earth.) Know any thing about this?

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