1. The motion of a particle is described by x=10sin(pi*t+pi/3). At what time in s is the potential energy equal to the kinetic energy? 2. I know these equations come into play Kinetic Energy K=1/2*m*ω^2*A^2*sin^2(ωt+φ) Kmax=1/2 k A^2 K=1/2 mv^2 Potential Energy U=1/2*k*A^2*cos^2(ωt+φ) U=1/2 kx^2 3. The attempt at a solution Well I know A=10, w=pi, T=pi seconds I am really stuck on where to go from here I think I am trying to make it too complicated. Any pointers would be great. Also if someone could explain what the phase constant does to the equation it would be very helpful.