a) A light with a wavelength of 500 nm illuminates two narrow slits that are 0.10 mm apart. If the viewing screen is 1.20 m from the slits calculate the distance between each maximum. b)how far would the fourth maximum be from the central maximum? a) Given: lambda = 500 x 10e-9 m d= 0.1 x 10e-3 m L= 1.2 m delta x = lambda x L/d =(500 x 10e-9 m) (1.2 m)/(0.1 x 10 e-3 m) =0.0006 m =6.0 x 10 e-3 Therefore, the distance between each maximum is 6.0 x 10 e-3 m b) Since the distance between each maximum is 6.0 x 10 e-3 m the fourth maximum would be 4 x (6.0 x 10 e-3 m) Therefore, 4 x (6.0 x 10 e-3 m) = 2.4 x 10 e-2 Therefore, the fourth maximum would be 2.4 x 10 e-2 m away from the central maximum. Does this look like I'm doing this question right to anybody?