- #1
laxboi33
- 9
- 0
Homework Statement
A crate is on a 20 degree plane where the coefficients of static and kinetic friction are .45 and .35 respectively. What is the acceleration of the crate?
Homework Equations
Mk= .35
Ms= .45
F= sin20 * mg (I think this is the net force?)
The Attempt at a Solution
F - Fk= M*A
(sin20 * mg) - (.35 * mg) = m * a
a = sin20 * g - .35 * g
a= .34 * 9.8 - .35 * 9.8
a = -.098
The answer in the book says 0. As I was writing this problem I think I figured it out. If sin 20 is the net force, then that would make net force less than the static friction which would give it 0 acceleration. Maybe I just miscalculated the net force. If so could someone explain to me what net force would be for this equation? Thanks, guys.