1. The problem statement, all variables and given/known data A crate is on a 20 degree plane where the coefficients of static and kinetic friction are .45 and .35 respectively. What is the acceleration of the crate? 2. Relevant equations Mk= .35 Ms= .45 F= sin20 * mg (I think this is the net force?) 3. The attempt at a solution F - Fk= M*A (sin20 * mg) - (.35 * mg) = m * a a = sin20 * g - .35 * g a= .34 * 9.8 - .35 * 9.8 a = -.098 The answer in the book says 0. As I was writing this problem I think I figured it out. If sin 20 is the net force, then that would make net force less than the static friction which would give it 0 acceleration. Maybe I just miscalculated the net force. If so could someone explain to me what net force would be for this equation? Thanks, guys.