- #1
roam
- 1,271
- 12
Hello!
Here's a question that I couldn't understand;
A canvas tent is to be constructed in the shape of a right-circular cone with the ground as base;
Using the volume V and curved surface area S of the cone,
[tex]V = \frac{1}{3}\pi r^2 h[/tex], [tex]S = \pi rl[/tex],
Find the dimensions of the cone that maximises the volume for the [tex]4 \sqrt{3 \pi}[/tex] m² of canvas material, and find this maximum volume.
I'd appreciate it if you could give me some hints and guidance so I can get started on this question. I really don't understand what this question means, and there are no measures of height, base, redius etc.. are given...
Thank you.
Here's a question that I couldn't understand;
A canvas tent is to be constructed in the shape of a right-circular cone with the ground as base;
Using the volume V and curved surface area S of the cone,
[tex]V = \frac{1}{3}\pi r^2 h[/tex], [tex]S = \pi rl[/tex],
Find the dimensions of the cone that maximises the volume for the [tex]4 \sqrt{3 \pi}[/tex] m² of canvas material, and find this maximum volume.
I'd appreciate it if you could give me some hints and guidance so I can get started on this question. I really don't understand what this question means, and there are no measures of height, base, redius etc.. are given...
Thank you.