The period of earth's orbit

  • Thread starter maddad
  • Start date
  • #1
2
0
Please help....
Given that the distance to the sun from the earth is 1.5*10^11 m and the the mass of the sun is 1.9*10^30 kg.
Using Keplers law find the period of the earth's orbit recorded in seconds; show how to express your anwser in years; and if your anwser does not agree with the accepted earth's orbital period of 365.25 days, explain the discrepancy.
I am totally lost using Keplers law, I need your help ... Thanks!
 
Last edited:

Answers and Replies

  • #2
tony873004
Science Advisor
Gold Member
1,752
143
You should post this in the homework help section.

Look up Kepler's laws. There are 3 of them. One deals with this exact problem. Look up Newton's modified form of Kepler's law. Look up the values that they gave you in the problem and confirm if they're the correct values.
 
  • #3
Janus
Staff Emeritus
Science Advisor
Insights Author
Gold Member
3,710
1,629
Moving to HW
 
  • #4
2
0
Dear Sir, this is my first time in a forum, and I don't know how to retrieve the posted information. Can you please explain how do I get the anwser to my problem> Thanks!
 
  • #5
tony873004
Science Advisor
Gold Member
1,752
143
You retrieve it by using your textbook. Look in the index for "Kepler's Laws", specifically his 3rd law. Or you can Google "Kepler's Laws" and "Newton's modified form of Kepler's Law".
 

Related Threads on The period of earth's orbit

  • Last Post
Replies
10
Views
3K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
1
Views
9K
  • Last Post
Replies
6
Views
6K
  • Last Post
Replies
3
Views
682
  • Last Post
Replies
1
Views
19K
  • Last Post
Replies
4
Views
8K
Replies
8
Views
5K
  • Last Post
2
Replies
42
Views
4K
Top