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The Photoelectric effect

  1. Dec 5, 2013 #1
    1. The problem statement, all variables and given/known data

    Suppose a filter allowed through only light of frequency fo (the cut-off frequency) or lower. In this case, what would the stopping potential be?


    2. Relevant equations

    KEmax = (charge of electron)(stopping potential) = hf - Work function, where Work function = hfcutoff

    3. The attempt at a solution

    Because the filter is now only allowing lights AT or BELOW the cutoff frequency, we can arrange our eaution as follows:

    (e)(Vstopping) = hf - hfcutoff = h(f-fcutoff). But because f = fcutoff, (e)(Vstopping) = 0. Since e has a value of 1.6 x 10^-19 C, this forces stopping potential to be 0. However: this was marked incorrect.

    Any suggestions or comments would be greatly appreciated!
     
  2. jcsd
  3. Dec 6, 2013 #2

    Redbelly98

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    Somehow, "work function" has become "h*fcutoff" in your work. That is not true. The work function of the material does not change just because the light has passed through a filter.
     
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