This is not homework, it is purely for my own enjoyment.(adsbygoogle = window.adsbygoogle || []).push({});

Say I have a lead sphere with a one meter radius, a mass of 465800N and a terminal velocity of 1290m/s. Say I also have a different spherical body of 685N. I now place the 685N body on one side of a seesaw of 20m in length and a height of 5m at the at the 10m mark.

How, from this information, can I work out how high I must drop the lead ball from to accelerate the 685N ball to >= 11200m/s? Also what is the relationship between mass and acceleration and how does it transfer to the other side of this idealized seesaw.

I'd be grateful if you didn't work it out but told me how to, as the working is what I find fun.

P.S I am ignoring things such as friction and assuming the 685N ball is launching vertically.

Thanks.

-R

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# Homework Help: The physics of a seesaw.

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