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**Q1.**

x

^{2}dy/dx + xy = x

^{2}sinx

I believe it is a separable equation (first order linear)

First step is to rewrite into standard form;

dy/dx + (xy)/x

^{2}= (x

^{2}sin(x))/x

^{2}

Then to calculate the integrating factor I(x);

I(x) = e

^{|(xy)/x2dx}= e

^{ylnx}= e

^{lnxy}= x

^{y}

Then i need to multiply both sides of the d.e. by I(x)