1. The problem statement, all variables and given/known data In an amusement park ride called The Roundup, passengers standinside a 16 m diameter rotating ring.After the ring has acquired sufficient speed, it tilts into avertical plane, as shown in Figure Part A Suppose the ring rotates once every 4.70 s. If a rider's mass is 53.0 kg,with how much force does the ring push on her at the top of the ride? There are several parts, but I want to do one piece at a time please 2. Relevant equations I think V(top)=r w = 2 pie r/ T T(top)=(m/r)(v^2 top)-mg 3. The attempt at a solution I tried V(top)=r w = 2 pie r/ T =(2 pie (16)/(2(4.70s)=10.69 m/s then T(top)=(m/r)(v^2 top)-mg =(53/16)(10.69 m/s)^2-53(9.8 m/s^2)= -140.86 N ?