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The specific of heat

  1. Sep 8, 2015 #1
    1. The problem statement, all variables and given/known data

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    2. Relevant equations
    Is my work right? This is the last attempt I got :/
    3. The attempt at a solution
    Specific heat of water = 4.187 J/g.K
    Heat released by hot metal = mass x specific heat x temperature change
    = 99 x c x (100 - 21.4) = 7781.4c
    Heat absorbed by water = mass x specific heat x temperature change
    = 403 x 4.187 x (21.4 - 20.0) = 2362.305 J
    Heat absorbed by container = mass x specific heat x temperature change
    = 212 x c x (21.4 - 20.0) = 296.8c
    Total heat released = total heat absorbed
    7781.4c = 2362.305 + 296.8c
    Specific heat of the metal = c = 0.3156 J/g.K = 0.3156 kJ/kg.K
     
    Last edited: Sep 8, 2015
  2. jcsd
  3. Sep 9, 2015 #2

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    Looks reasonable.
     
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