A copper wire, whose cross sectional area is 1.1 x 10 ^ -6 m^2, has a linear density of 7.0 x 10^-3 Kg/m and is strung between two walls. At the ambient temperature, a transverse wave travels with a speed of 46 m/s on this wire. The coefficient of linear expansion for copper is 17 x 10^-6 , and Youngs modulus for copper is 1.1 x 10^11 N/m^2. What will be the speed of the wave when the temperature is lowered by 14 C? v = √(F/(m⁄L)) (1) F = Y(∆L/L0)A (2) ∆L = α.L0.∆T ⇒ ∆L/L0 = α.∆T (3) A = 1.1 x 10^-6 m^2 m/L = 7 x 10^-3 Kg/m α = 17 x 10^-6 Y = 1.1 x 10^11 N/m^2 v = 46 m/s We can write formula (1) such this: v = √((Y.α.∆T.A)/(m/L)) and now substitute all the variables in the above formula for finding ∆T. But now I don't know what do I have to do, ∆T2 to find the speed of the wave.