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**Evaluate the following integral using integration by substitution: http://img254.imageshack.us/img254/750/44900023cm4.png [Broken]**[/URL]

**Here is my attempt:**

Let x = sinu, then dx/du = cosu

Substituting gives, ∫1/(1-sin2u)×cosu du

= ∫1/(1-sin2u)×cosu du

= ∫cosu/√cos2u du

= ∫cosu/cosu du

= ∫1 du = u + c = sin-1x + c

Am I right? Did I get the right solution?

Regards,

Let x = sinu, then dx/du = cosu

Substituting gives, ∫1/(1-sin2u)×cosu du

= ∫1/(1-sin2u)×cosu du

= ∫cosu/√cos2u du

= ∫cosu/cosu du

= ∫1 du = u + c = sin-1x + c

Am I right? Did I get the right solution?

Regards,

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