(adsbygoogle = window.adsbygoogle || []).push({}); Hello!

The following is my problem (a question from an old exam paper);

http://img341.imageshack.us/img341/5142/69855901wv3.gif [Broken]

Well, I'm stuck on part c and d.

I already got the correct answers for a & b;

[tex]v = \frac{\omega}{k} => \frac{4}{3} = 1.3 m/s[/tex]

[tex]K = \frac{2\pi}{\lambda} => \lambda = 2.09 m[/tex]

[tex]v = f\lambda => f = 0.65 Hz[/tex]

[tex]v = \sqrt{\frac{T}{\mu}} => 1.3 = \sqrt{\frac{T}{4}} => T = 7.1[/tex]

I checked the answers and it is correct up to this point. Now I don't know how to do question c. What is it meant by "transverse speed". What formula should I use?

(The right answer is -0.022 m/s is the transverse speed at x = 1 & t = 1)

I don't know which formula to use...

Thanks.

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# Homework Help: The Transverse Speed

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